11+x^2=9x+4

Solution for 11+x^2=9x+4 equation:

11+x^2=9x+4

We move all terms to the left:

11+x^2-(9x+4)=0

We get rid of parentheses

x^2-9x-4+11=0

We add all the numbers together, and all the variables

x^2-9x+7=0

a = 1; b = -9; c = +7;
Δ = b2-4ac
Δ = -92-4·1·7
Δ = 53
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(-9)-\sqrt{53}}{2*1}=\frac{9-\sqrt{53}}{2}
$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(-9)+\sqrt{53}}{2*1}=\frac{9+\sqrt{53}}{2}
$